type a = {id?:number,phone?:string}|{id?:number,name?:string}
type b = ?a
期待: type b = 'id'|'phone'|'name'
This topic created in 2357 days ago, the information mentioned may be changed or developed.
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CAzeMay 26, 2020
1
a & {name?: string} 就好了
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TarotVoyagerMay 26, 2020
3
其实更困惑的是
type a = { id?: number, phone?: string, name?: string } 为什么不能是这个格式…… |
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horizonMay 26, 2020
4
interface A {
id?: string; phone?: string; } interface B { id?: string; name?: string; } type C = keyof (A & B); |
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horizonMay 26, 2020
5
我看错了，无视。。
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TarotVoyagerMay 26, 2020
6
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TarotVoyagerMay 26, 2020
8
@ytxbnahn #7 上面回复的 stackoverflow 链接应该能解决这个问题，如果用的 ts 2.8 的话
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