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css3
V2EX  ›  Python

小白问个问题

  •  
  •   css3 · Dec 10, 2018 · 2604 views
    This topic created in 2891 days ago, the information mentioned may be changed or developed.
    a = [1,2,4]
    b = [1,2,3,4,5,6]
    

    想输出一个结果,c 是 a 和 b 的并集,但每个值要标明是否是交集,如

    c = {"1" :True, "2" :True, "3" :False, "4": True, "5": False, "6":False}
    

    应该怎么处理?😭

    9 replies  •  2018-12-11 10:35:41 +08:00
    kkkkkrua
    kkkkkrua
    Dec 10, 2018
    1
    leetcode,交集
    asLw0P981N0M0TCC
    asLw0P981N0M0TCC
    Dec 10, 2018
    2
    都是有序的话 我记得有个是 2 个从头互相比较的 好像要额外空间存储
    AlisaDestiny
    AlisaDestiny
    Dec 10, 2018❤️1
    3
    ```python
    a = [1,2,4]
    b = [1,2,3,4,5,6]

    u = set(a+b)
    r = {}
    for x in u:
    r[str(x)] = (x in a and x in b)
    print(r)
    ```
    css3
    css3
    OP
    Dec 10, 2018
    4
    @kkkkkrua @qwertyzzz @AlisaDestiny

    感谢各位☺
    nichijou
    nichijou
    Dec 10, 2018❤️1
    5
    第一个依次存入哈希字典, key 是 number, value 是 false

    然后遍历第二个,有的改 true, 没的存 key: false
    smdbh
    smdbh
    Dec 10, 2018
    6
    L3 +1
    zxcvsh
    zxcvsh
    Dec 10, 2018 via iPhone
    7
    推荐 3 楼,5 楼也可行,但是 3 楼相对有优化
    v2gba
    v2gba
    Dec 10, 2018
    8
    >>> s1 = collections.Counter(a+b)
    >>> s2 = collections.Counter(set(a+b))
    >>> s1.subtract(s2)
    >>> s1
    Counter({1: 1, 2: 1, 4: 1, 3: 0, 5: 0, 6: 0})
    css3
    css3
    OP
    Dec 11, 2018
    9
    @nichijou @smdbh @zxcvsh @MrGba2z
    多谢😀
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