数据库中 tag_id=1 的有 5 项
实际输出只有 4 项
第一条哪去了呢
代码
while($total_row = mysqli_fetch_array($total_result))
{
echo $total_row['tag_id'] . " " . $total_row['topic_id'];
echo "<br />";
}
This topic created in 3108 days ago, the information mentioned may be changed or developed.
数据库中 tag_id=1 的有 5 项
实际输出只有 4 项
第一条哪去了呢
代码
while($total_row = mysqli_fetch_array($total_result))
{
echo $total_row['tag_id'] . " " . $total_row['topic_id'];
echo "<br />";
}
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msg7086May 8, 2018
1
请求的代码在哪呢。
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2
@msg7086 #1
请求的代码 $total_sql="SELECT * FROM topic_tag WHERE tag_id = 1"; $total_result =mysqli_query($conn,$total_sql); $total_row=mysqli_fetch_row($total_result); |
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msg7086May 8, 2018
3
$total_row=mysqli_fetch_row($total_result); 不就把第一行请求走了吗。
while 里就从第二行开始读了呀？ |
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4
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msg7086May 8, 2018
5
把这行多余的读取第一行然后扔掉的代码删掉。
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6
@msg7086 #5
tks,搞定 |
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