就是我之前用 find_all 定位了一个标签，然后我想再次用 find_all 查询第一次 find_all 的结果，可是却失败了
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1
或者可不可以把 find_all 的结果全部转换成 string ，
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b1eberg0nOct 25, 2016
2
a = soup.findall('a')
b = a[0].findall('b') |
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Arthur2e5Oct 25, 2016
3
改写一下 @b1eberg0n ，来个范围攻击的……
a_b = [a.findall('b') for a in soup.findall('a')] a_b_flat = [result for a in soup.findall('a') for result in a.findall('b')] |
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orange88Oct 25, 2016 via Android
6
li 是 none ，上一个没找到？
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orange88Oct 25, 2016 via Android
8
li[0].findall
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syahdOct 25, 2016 via Android
10
find_all 返回的结果是个 list ，要其中的结果得把它迭代一遍才行，最好再加个异常处理，防止出现你这样的情况
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practicerOct 25, 2016
11
get_all_secondary_elements(bs)
try: top_elements = bs.find_all(...) for top_element in top_elements: secondary_elements = top_element.find_all(...) if secondary_elements is not None: yield secondary_elements except (AttributeError, TypeError): yield secondary_elements = list(get_all_secondary_elements) |
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wyntergregOct 25, 2016
12
转成 tag 再 findall
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b1eberg0nOct 25, 2016
13
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